Gujarati
Hindi
1. Electric Charges and Fields
normal

A thin spherical conducting shell of radius $R$ has a charge $q$ . Another charge $Q$ is placed at the centre of the shell. The electrostatic potential at a point $P$ at a distance $R/2$ from the centre of the shell is

A$\frac{{2Q}}{{4\pi { \in _0}R}}$
B$\frac{{2Q}}{{4\pi { \in _0}R}} - \frac{{2q}}{{4\pi { \in _0}R}}$
C$\frac{{2Q}}{{4\pi { \in _0}R}} + \frac{q}{{4\pi { \in _0}R}}$
D$\frac{{(q + Q)}}{{4\pi { \in _0}R}}\frac{2}{R}$

Solution

$V_{p}=V_{Q}+V_{q}$
$ = \frac{{kQ}}{{R/2}} + \frac{{kq}}{R} = \frac{{2Q}}{{4\pi { \in _0}R}} + \frac{q}{{4\pi { \in _0}R}}$
Standard 12
Physics

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